81x^2-48x^2=-64x

Solution for 81x^2-48x^2=-64x equation:

81x^2-48x^2=-64x

We move all terms to the left:

81x^2-48x^2-(-64x)=0

We add all the numbers together, and all the variables

33x^2-(-64x)=0

We get rid of parentheses

33x^2+64x=0

a = 33; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·33·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*33}=\frac{-128}{66}
=-1+31/33
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*33}=\frac{0}{66}
=0
$